document.write( "Question 957950: The length is 4 units less than 3 times the width. The perimeter is 22 units more than twice the width. What is the length, width, and perimeter? \n" ); document.write( "
Algebra.Com's Answer #585445 by macston(5194)\"\" \"About 
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W=width; L=3W-4; P=perimeter=2W+22
\n" ); document.write( "P=2(L+W)
\n" ); document.write( "2W+22=2(3W-4+W) Divide each side by 2.
\n" ); document.write( "W+11=4W-4 Add4 to each side.
\n" ); document.write( "W+15=4W Subtract W from each side.
\n" ); document.write( "15=3W Divide eachside by 3
\n" ); document.write( "5=W ANSWER 1: The width is 5
\n" ); document.write( "L=3W-4=3(5)-4=15-4=11 ANSWER 2: The length is 11.
\n" ); document.write( "P=2(L+W)=2(11+5)=2(16)=32 ANSWER 3: The perimeter is 32
\n" ); document.write( "CHECK:
\n" ); document.write( "Perimeter=2(L+W)
\n" ); document.write( "2W+22=2(11+5)
\n" ); document.write( "2(5)+22=2(16)
\n" ); document.write( "10+22=32
\n" ); document.write( "32=32
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