document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=957926>Question 957926</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The value of an uncirculated 'Mint state-65' 1950 Jefferson nickle minted in Denver is 4/3 the value a 1945 nickle minted in Philadelphia in similar condition. Together the total value of the two coins are $42. What is the value of each coin?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #585441 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=585441\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=value Philadelphia coin; D=value Denver coin=4/3P<BR>\n" );
document.write( "P+D=$42 Substitute for D<BR>\n" );
document.write( "P+4/3P=$42<BR>\n" );
document.write( "7/3P=$42 Multiply each side by 3/7.<BR>\n" );
document.write( "P=$126/7=$18 ANSWER 1: The coin minted in Philadelphia is valued at $18.<BR>\n" );
document.write( "D=4/3(P)=4/3($18)=$72/3=$24 ANSWER 2: The coin minted in Denver is valued at $24. </SPAN>\n" );
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