document.write( "Question 81641: Lane invested $14,000, part at 15% and part at 2%. If the total interest at the end of the year is $1,060, how much did she invest at 15%? \n" ); document.write( "
Algebra.Com's Answer #58542 by checkley75(3666)\"\" \"About 
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.15x+.02(14000-x)=1060
\n" ); document.write( ".15x+280-.02x=1060
\n" ); document.write( ".15x-.02x=1060-280
\n" ); document.write( ".13x=780
\n" ); document.write( "x=780/.13
\n" ); document.write( "x=6000 answer for the amount invested @ 155.
\n" ); document.write( "proof
\n" ); document.write( ".15*6000+.02*8000=1060
\n" ); document.write( "900+160=1060
\n" ); document.write( "1060=1060
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