document.write( "Question 957503: I'm don't understanding how to solve this question: \r
\n" ); document.write( "\n" ); document.write( "The graph of a line passes through the x-intercept of y-20=2/11(x-31) and is perpendicular to the line y=1/7x+7 . The equation of the line, written in Slope-Point form, is y-p = m(x-q). what is the value of m*q ?
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Algebra.Com's Answer #585401 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
First find the x-intercept of
\n" ); document.write( "\"y-20=%282%2F11%29%28x-31%29\"
\n" ); document.write( "So solve for \"x\" when \"y=0\"
\n" ); document.write( "\"-20=%282%2F11%29%28x-31%29\"
\n" ); document.write( "\"-110=x-31\"
\n" ); document.write( "\"x=-79\"
\n" ); document.write( "So the x-intercept is (-79,0).
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\n" ); document.write( "Perpendicular lines have slopes that are negative reciprocals.
\n" ); document.write( "\"m%5Bp%5D%2A%281%2F7%29=-1\"
\n" ); document.write( "\"m%5Bp%5D=-7\"
\n" ); document.write( "So then using the point-slope form,
\n" ); document.write( "\"y-0=-7%28x-%28-79%29%29\"
\n" ); document.write( "\"y=-7%28x%2B79%29\"
\n" ); document.write( "\"m=-7\"
\n" ); document.write( "\"q=-79\"
\n" ); document.write( "\"m%2Aq=553\"
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