document.write( "Question 957764: A photograph has an area of 24 square inches and the length is 2 inches more than the width. Find the length and width of the photograph.\r
\n" ); document.write( "\n" ); document.write( "If x represents the width of the photograph, select all the equations that could be used to solve this problem \n" ); document.write( "
Algebra.Com's Answer #585394 by addingup(3677)\"\" \"About 
You can put this solution on YOUR website!
If x represents the width of the photograph, select all the equations that could be used to solve this problem:
\n" ); document.write( "L = 2 + W Length equals 2 more than the Width
\n" ); document.write( "W = Width
\n" ); document.write( "How to solve it:
\n" ); document.write( "(2+W)(W) = 24 Multiply on the left to get rid of the parenthesis:
\n" ); document.write( "W^2 + 2W = 24 Subtract 24 on both sides:
\n" ); document.write( "W^2 + 2W - 24= 0 Now we have a quadratic trinomial we can factor as the product of two binomials. We need four terms, in two pairs of two, such that the first terms multiply to W^2, the outer terms and the inner terms add/subtract to 2W, and the Last terms multiply to -24 (F.O.I.L.):
\n" ); document.write( "(W-4)(W+6) = 0 Now we solve for each binomial equation separately:
\n" ); document.write( "W-4=0 or W+6= 0 Add 4 on both sides, 1st equation, and subtract 6 on both sides, 2nd equation:
\n" ); document.write( "W= 4 or w= -6 We can't use the negative, toss it out and we keep the 4.
\n" ); document.write( "Check:
\n" ); document.write( "W= 4
\n" ); document.write( "L= 2+4= 6
\n" ); document.write( "Area: 4*6=24 Our answer is correct.
\n" ); document.write( " \n" ); document.write( "
\n" );