document.write( "Question 957764: A photograph has an area of 24 square inches and the length is 2 inches more than the width. Find the length and width of the photograph.\r
\n" ); document.write( "\n" ); document.write( "If x represents the width of the photograph, select all the equations that could be used to solve this problem
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Algebra.Com's Answer #585382 by macston(5194)\"\" \"About 
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W=width; L=length=W+2in; A=area=24 sq in
\n" ); document.write( "\"A=LW\" Substitute for L
\n" ); document.write( "\"A=%28W%2B2%29%28W%29\"
\n" ); document.write( "\"24in%5E2=W%5E2%2B2W\" Subtract 24 in^2 from wach side.
\n" ); document.write( "\"0=W%5E2%2B2W-24\"
\n" ); document.write( "\"0=%28W%2B6%29%28W-4%29\"
\n" ); document.write( "\"W%2B6=0\" \"or\" \"W-4=0\"
\n" ); document.write( "\"W=-6\" \"or\" \"W=4\" ANSWER1: The width is 4 inches.
\n" ); document.write( "L=W+2in=4in+2in=6in ANSWER 2: The length is 6 inches.
\n" ); document.write( "CHECK:
\n" ); document.write( "\"A=LW\"
\n" ); document.write( "\"24in%5E2=%286in%29%284in%29\"
\n" ); document.write( "\"24in%5E2=24in%5E2\"
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