document.write( "Question 957827: Note: Remember to show all the steps that you use to solve the problem. You can use the comments field to explain your work. Your teacher will review each step of your response to ensure you receive proper credit for your answer.\r
\n" ); document.write( "\n" ); document.write( "What is the solution to the proportion?\r
\n" ); document.write( "\n" ); document.write( "\"+3y-8%2F+12+=+y%2F5+\"
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Algebra.Com's Answer #585328 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
\"+3y-8%2F+12+=+y%2F5+\"
\n" ); document.write( "CROSS MULTIPLY
\n" ); document.write( "12Y=5(3y-8)
\n" ); document.write( "12y=15y-40
\n" ); document.write( "12y-15y=-40
\n" ); document.write( "-3y=-40
\n" ); document.write( "y=-40/-3
\n" ); document.write( "y=40/3 ans.
\n" ); document.write( "proof:
\n" ); document.write( "(3*40/3-8)/12=(40/3)/5
\n" ); document.write( "(40-8)/12=40/3*1/5
\n" ); document.write( "32/12=40/15
\n" ); document.write( "8/3=8/3
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