document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=81563>Question 81563</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve for x\r<BR>\n" );
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document.write( "3x + 1/2 = 1/4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #58528 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=58528\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve for x<BR>\n" );
document.write( "3x + 1/2 = 1/4<BR>\n" );
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document.write( "multiply equation by 4 to get rid of the denominators:<BR>\n" );
document.write( "12x + 2 = 1<BR>\n" );
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document.write( "12x= 1 - 2<BR>\n" );
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document.write( "x = -1/12<BR>\n" );
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document.write( "Check for x= -1/12 in the original equation:<BR>\n" );
document.write( "3(-1/12) + 1/2 = <BR>\n" );
document.write( "-3/12 + 1/2 =<BR>\n" );
document.write( "-3/12 + 6/12 = +3/12 which is 1/4<BR>\n" );
document.write( " </SPAN>\n" );
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