document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=957613>Question 957613</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Premises: S v B , B&#8835;D, S&#8835;G<BR>\n" );
document.write( "Conclusion: D v G<BR>\n" );
document.write( "I am trying to work down from the premises but cant find way to get to the conclusion. Any help would be appreciated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #585250 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=585250\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You use the constructive dilemma rule here. It happens in two steps. First you conjunct B&#8835;D, S&#8835;G together to get (B&#8835;D)&(S&#8835;G). Then you'll use constructive dilemma with (B&#8835;D)&(S&#8835;G) and  S v B to get D v G\r<BR>\n" );
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document.write( "Check out this list of rules:\r<BR>\n" );
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document.write( "<a  rel=nofollow HREF=\"http://www.butte.edu/~wmwu/iLogic/3.3/iLogic_3_3.html\">http://www.butte.edu/~wmwu/iLogic/3.3/iLogic_3_3.html</a>\r<BR>\n" );
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document.write( "and specifically the constructive dilemma rule </SPAN>\n" );
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