document.write( "Question 957676: Solve. Factor by graphing.\r
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Algebra.Com's Answer #585237 by Edwin McCravy(20054)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "I think you meant \"Factor by GROUPing, not \"GRAPHing\".\r\n" );
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document.write( "\"x%5E3%2B5x%5E2-x-5\"\"%22%22=%22%22\"\"%220%22\"\r\n" );
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document.write( "Factor x2 out of the first two terms and get x2(x+5)\r\n" );
document.write( "Factor -1 out of the last two terms and get -1(x+5)\r\n" );
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document.write( "\"x%5E2red%28%28x%2B5%29%29-1red%28%28x%2B5%29%29\"\"%22%22=%22%22\"\"%220%22\"\r\n" );
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document.write( "There is a common factor (x+5) so factor it out:\r\n" );
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document.write( "\"red%28%28x%2B5%29%29%28x%5E2-1%29\"\"%22%22=%22%22\"\"%220%22\"\r\n" );
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document.write( "Factor x2-1 as (x-1)(x+1)\r\n" );
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document.write( "\"red%28%28x%2B5%29%29%28x-1%29%28x%2B1%29\"\"%22%22=%22%22\"\"%220%22\"\r\n" );
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document.write( "Set each factor = 0 and get\r\n" );
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document.write( "x+5 = 0,  x-1 = 0,  x+1 = 0\r\n" );
document.write( "  x = -5,   x = 1     x = -1\r\n" );
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document.write( "Edwin
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