document.write( "Question 957612: The length of a rectangle is 3 less than 5 times of its width.
\n" ); document.write( "write a simplified algebraic expression for the perimeter of a rectangle.
\n" ); document.write( "if the rectangle width is tripled and its length is doubled the perimeter of new rectangle is 92 cm greater than original perimeter.
\n" ); document.write( "Find the area of the original rectangle.
\n" ); document.write( "PLZZZ explain how u solved this?
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #585222 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
W=width; L=length=5W-3; P=perimeter
\n" ); document.write( "Original rectangle:
\n" ); document.write( "P=2(L+W) Substitute for L
\n" ); document.write( "P=2((5W-3)+W)=6W-3=12W-6
\n" ); document.write( "Original perimeter is 12W-6
\n" ); document.write( "New rectangle:
\n" ); document.write( "\"W%5Bn%5D=3W\"; \"L%5Bn%5D=2L\"=\"10W-6\"
\n" ); document.write( "=\"2%2813W-6%29=26W-12\"
\n" ); document.write( "New perimeter is 26W-12
\n" ); document.write( "New perimeter-original perimeter=92 cm
\n" ); document.write( "\"P%5Bn%5D-P=92cm\"
\n" ); document.write( "\"%2826W-12%29-%2812W-6%29=92cm\"
\n" ); document.write( "\"14W-6=92cm\"
\n" ); document.write( "\"14W=98cm\"
\n" ); document.write( "\"W=7cm\" The original width was 7cm.
\n" ); document.write( "L=5W-3=5(7cm)-3=35cm-3cm=32cm The original length was 32cm.
\n" ); document.write( "Area=L*W=32cm*7cm=224 sq cm
\n" ); document.write( "ANSWER: The area of the original rectangle is 224 square centimeters.
\n" ); document.write( "CHECK
\n" ); document.write( "New Perimeter-Original Perimeter=92cm
\n" ); document.write( "2(2L+3W)-2(L+W)=92cm
\n" ); document.write( "2(64cm+21cm)-2(32cm+7cm)=92cm
\n" ); document.write( "2(85cm)+2(39cm)=92cm
\n" ); document.write( "170cm-78cm=92cm
\n" ); document.write( "92cm=92cm\r
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