document.write( "Question 957614: The length of a rectangle is 3 less than 5 times of its width.
\n" ); document.write( "write a simplified algebraic expression for the perimeter of a rectangle.
\n" ); document.write( "if the rectangle width is tripled and its length is doubled the perimeter of new rectangle is 92 cm greater than original perimeter.
\n" ); document.write( "Find the area of the original rectangle.
\n" ); document.write( "PLZZZ explain how u solved this?
\n" ); document.write( "and fast plz!!!!
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Algebra.Com's Answer #585208 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
Length, L, width w.
\n" ); document.write( "The length of a rectangle is 3 less than 5 times of its width.
\n" ); document.write( "\"L=-3%2B5w\".\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "p, perimeter of the rectangle.
\n" ); document.write( "\"p=2L%2B2w\"
\n" ); document.write( "\"p=2%285w-3%29%2B2w\"
\n" ); document.write( "\"p=10w-6%2B2w\"
\n" ); document.write( "\"highlight_green%28p=12w-6%29\"\r
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\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "if the rectangle width is tripled and its length is doubled the perimeter of new rectangle is 92 cm greater than original perimeter.\r
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\n" ); document.write( "\n" ); document.write( "Now the dimensions are changed to width \"3w\" and length \"2%285w-3%29=10w-6\". The new perimeter is given as \"12w-6%2B92\".\r
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\n" ); document.write( "\n" ); document.write( "The question is, find the area of the original rectangle, but you need to solve for w, and then for L so that the area can be calculated. Return to the perimeter formula for using with the new perimeter situation.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"p=2%2AnewLength%2B2%2AnewWidth\"
\n" ); document.write( "\"12w-6%2B92=2%2810w-6%29%2B2%283w%29\", with the expressions substituted.
\n" ); document.write( "\"12w%2B86=10w-12%2B6w\"
\n" ); document.write( "\"86=4w-12\"
\n" ); document.write( "\"4w=92\"
\n" ); document.write( "\"highlight%28w=23%29\"----------Use the given formula for L to find value of L.\r
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\n" ); document.write( "\n" ); document.write( "\"L=5w-3\"
\n" ); document.write( "\"L=5%2A23-3\"
\n" ); document.write( "\"highlight%28L=112%29\"\r
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\n" ); document.write( "\n" ); document.write( "Original rectangle's area, \"highlight%28w%2AL=23%2A112=highlight%282576%29%29\".
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