document.write( "Question 957618: 4 times the first of three consecutive EVEN integers is 6 more then the product of 2 and the 3rd integer.Find the integers. I keep getting odd numbers for my integers instead of even. I tried this, but I must be setting it up wrong....
\n" ); document.write( "integers are : x, x + 2, x + 4
\n" ); document.write( "set it up like this : 4(x) = 2(x + 4) + 6
\n" ); document.write( "that does not work....what am I doing wrong ? \n" ); document.write( "
Algebra.Com's Answer #585198 by Alan3354(69443)\"\" \"About 
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4 times the first of three consecutive EVEN integers is 6 more then the product of 2 and the 3rd integer.Find the integers. I keep getting odd numbers for my integers instead of even. I tried this, but I must be setting it up wrong....
\n" ); document.write( "integers are : x, x + 2, x + 4
\n" ); document.write( "set it up like this : 4(x) = 2(x + 4) + 6
\n" ); document.write( "that does not work....what am I doing wrong ?
\n" ); document.write( "---------------
\n" ); document.write( "4x = 2*(x+4) + 6
\n" ); document.write( "4x = 2x+8 + 6 = 2x + 14
\n" ); document.write( "x = 7
\n" ); document.write( "===================
\n" ); document.write( "There's no solution with even integers.
\n" ); document.write( "----
\n" ); document.write( "Try 6, 8 & 10
\n" ); document.write( "4*6 =? 2*10 + 6 NG
\n" ); document.write( "---
\n" ); document.write( "Try 8, 10 & 12
\n" ); document.write( "4*8 =? 2*12 + 6 NG \n" ); document.write( "
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