document.write( "Question 957389: A rectangle is 4cm longer than it is wide. If it is x cm wide and has an area of 77cm squared. Form an equation in x and solve it to find the dimensions of the rectangle
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Algebra.Com's Answer #585148 by satyareddy(3)\"\" \"About 
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width=x cm,
\n" ); document.write( "Let length be l cm
\n" ); document.write( "l-x=4 cm =>l = 4+x---------(1)
\n" ); document.write( "lx=77
\n" ); document.write( "substituting (1) in lx=77
\n" ); document.write( "(4+x)x=77
\n" ); document.write( "4x+x^2=77
\n" ); document.write( "x^2+4x-77=0
\n" ); document.write( "x^2+11x-7x-77=0
\n" ); document.write( "x(x+11)-7(x+11)=0
\n" ); document.write( "(x+11)(x-7)=0
\n" ); document.write( "x=-11,7
\n" ); document.write( "since width cannot take negative value x=7
\n" ); document.write( "substituting x=7 in (1)
\n" ); document.write( "l=4+7=11
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