document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=957541>Question 957541</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A train moves in a speed of 300 K/H. If the speed is increased by 5 K/H the time will decrease by 2 hours. What is the speed of the train. Show your work. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #585146 by </B><A HREF=/tutors/aboutme.mpl?userid=satyareddy22><B>satyareddy22(84)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=satyareddy22><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=585146\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> speed(S)=300 k/h,Time(T)=t<BR>\n" );
document.write( "when S is increased by 5 k/h  then S = 300+5=305 k/h,<BR>\n" );
document.write( "Time is decreased by 2 hours =>T =t-2<BR>\n" );
document.write( "Distance = S * T<BR>\n" );
document.write( "Distance is same in both cases<BR>\n" );
document.write( "so, 300 t = 305(t-2)<BR>\n" );
document.write( "300t = 305t - 305 * 2<BR>\n" );
document.write( "305t - 300t = 610<BR>\n" );
document.write( "5t=610<BR>\n" );
document.write( "t=610/5 =122h </SPAN>\n" );
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