document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=957363>Question 957363</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A distance of 33 KM is covered in 1 hr. 12 minutes. If the first 15 KM is covered at the speed of 25 KM per hour. Find the speed during the remaining distance. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #585140 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=585140\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A distance of 33 KM is covered in 1 hr. 12 minutes. If the first 15 KM is covered at the speed of 25 KM per hour. Find the speed during the remaining distance.<BR>\n" );
document.write( "***l<BR>\n" );
document.write( "let x=travel time for first 15 km<BR>\n" );
document.write( "travel time=distance/speed<BR>\n" );
document.write( "x=15 km/25 km/hr<BR>\n" );
document.write( "x=(15/25)=(3/5)hr=36 min<BR>\n" );
document.write( "..<BR>\n" );
document.write( "1 hr 12 min=72 min<BR>\n" );
document.write( "72-36=36=travel time of remaining distance<BR>\n" );
document.write( "remaining distance=33-15=18 km<BR>\n" );
document.write( "speed=18/(36/60)=30 <BR>\n" );
document.write( "speed during the remaining distance=30 mph </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );