document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=957509>Question 957509</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Steps on how to solve (5x-4y)cubed\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #585132 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39620)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=585132\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Treat each term in the binomial as a separate variable.  The pattern for the coefficients would go like, 1, 3, 3, 1, in accordance to what you would find if you were to do the cubing with a simple model such as  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28a%2Bb%29%5E3 ALIGN=MIDDLE  ALT=\"%28a%2Bb%29%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or referring to the Binomial Theorem.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2A%285x%29%5E3%2B3%285x%29%5E2%28-4y%29%2B3%285x%29%28-4y%29%5E2%2B1%28-4y%29%5E3 ALIGN=MIDDLE  ALT=\"1%2A%285x%29%5E3%2B3%285x%29%5E2%28-4y%29%2B3%285x%29%28-4y%29%5E2%2B1%28-4y%29%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "still requiring a bit more simplifying to finish.\r<BR>\n" );
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