document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=957523>Question 957523</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much 20% alcohol is required to make 1L of 10% alcohol? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #585130 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=585130\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Your intuition should tell you that 10% is half of 20%, so you would take 1 L of 20%, add 1 L of water, and you have 10% alcohol.\r<BR>\n" );
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document.write( "A more formal description is here:<BR>\n" );
document.write( "<a  rel=nofollow HREF=\"http://www.algebra.com/my/Two-Part-Mixture-with-one-material-quantity-unknown.lesson?content_action=show_dev\">Mixture: one material quantity unknown</a><BR>\n" );
document.write( "http://www.algebra.com/my/Two-Part-Mixture-with-one-material-quantity-unknown.lesson?content_action=show_dev </SPAN>\n" );
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