document.write( "Question 957518: a man invest 3,000 dollars at a certain rate and 4,000 dollars at rate of 2/3 as high. his annual income from the two investments 180 dollars. find the interest rates? \n" ); document.write( "
Algebra.Com's Answer #585123 by macston(5194) You can put this solution on YOUR website! \n" ); document.write( "i=certain rate \n" ); document.write( "$3000i+$4000(2/3)i=180 \n" ); document.write( "$3000i+$2667i=180 \n" ); document.write( "5667i=$180 Divide each side by 5667 \n" ); document.write( "i=3.2% ANSWER 1: The certain interest rate was 3.2% \n" ); document.write( "2/3i=2.1% ANSWER 2: The lower interest rate was 2.1% \n" ); document.write( "CHECK \n" ); document.write( "$3000i+$4000(2/3i)=$180 \n" ); document.write( "$3000(0.032)+$4000(0.021)=$180 \n" ); document.write( "$96+$84=$180 \n" ); document.write( "$180=$180 \n" ); document.write( " \n" ); document.write( " |