document.write( "Question 957387: Mr Haseeb has Rs 300,000,part at 9% and part at 8%.if total amount from two investment is Rs 25800,how much is invested at 9% and how much at 8%? \n" ); document.write( "
Algebra.Com's Answer #585117 by macston(5194)![]() ![]() You can put this solution on YOUR website! N=amount at 9%; E=amount at 8% \n" ); document.write( "N+E=300000 \n" ); document.write( "N=300000-E \n" ); document.write( "0.08E+0.09N=25800 Substitute for N. \n" ); document.write( "0.08E+0.09(300000-E)=25800 \n" ); document.write( "0.08E+27000-0.09E=25800 Subtract 27000 from each side. \n" ); document.write( "-0.01E=-1200 Divide each side by 0.01. \n" ); document.write( "E=120000 ANSWER 1: Rs 120000 was invested at 8%. \n" ); document.write( "N=300000-E=300000-120000=180000 ANSWER 2: Rs 180000 was invested at 9%. \n" ); document.write( "CHECK: \n" ); document.write( "0.08E+0.09N=25800 \n" ); document.write( "0.08(120000)+0.09(180000)=25800 \n" ); document.write( "9600+16200=25800 \n" ); document.write( "25800=25800 \n" ); document.write( " |