document.write( "Question 957387: Mr Haseeb has Rs 300,000,part at 9% and part at 8%.if total amount from two investment is Rs 25800,how much is invested at 9% and how much at 8%? \n" ); document.write( "
Algebra.Com's Answer #585117 by macston(5194)\"\" \"About 
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N=amount at 9%; E=amount at 8%
\n" ); document.write( "N+E=300000
\n" ); document.write( "N=300000-E
\n" ); document.write( "0.08E+0.09N=25800 Substitute for N.
\n" ); document.write( "0.08E+0.09(300000-E)=25800
\n" ); document.write( "0.08E+27000-0.09E=25800 Subtract 27000 from each side.
\n" ); document.write( "-0.01E=-1200 Divide each side by 0.01.
\n" ); document.write( "E=120000 ANSWER 1: Rs 120000 was invested at 8%.
\n" ); document.write( "N=300000-E=300000-120000=180000 ANSWER 2: Rs 180000 was invested at 9%.
\n" ); document.write( "CHECK:
\n" ); document.write( "0.08E+0.09N=25800
\n" ); document.write( "0.08(120000)+0.09(180000)=25800
\n" ); document.write( "9600+16200=25800
\n" ); document.write( "25800=25800
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