document.write( "Question 957496: a train covers a distance of 720 km at a speed of x km/h. On the return journey, it travels at an average speed of y km/h and completes the whole journey in an hour less. if the speed during the return journey was 10 km/h more, what were the speeds in m/s? \r
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document.write( "is there a formula to use? \n" );
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Algebra.Com's Answer #585116 by macston(5194)![]() ![]() You can put this solution on YOUR website! a train covers a distance of 720 km at a speed of x km/h. On the return journey, it travels at an average speed of y km/h and completes the whole journey in an hour less. if the speed during the return journey was 10 km/h more, what were the speeds in m/s? \n" ); document.write( "distance=720km; original speed=x km/hr; return speed=y km/hr=x+10 km/hr \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "-x^2-10x+7200=0
\n" ); document.write( "\n" ); document.write( "x=80 Original speed was 80 km/hr. \n" ); document.write( "80km/hr+10km/hr=90km/hr Return speed was 90 km/hr. \n" ); document.write( "80km/hr(1000m/km)(1hr/3600sec)=22.22 m/sec Original speed was 22.22 meters per second. \n" ); document.write( "90km(1000m/1km)(1hr/3600sec)=25 m/sec Return speed was 25 meters per second. \n" ); document.write( "CHECK: \n" ); document.write( "(720km/80km/hr)-1hr=720km/90km/hr \n" ); document.write( "9hrs-1hrs=8hrs \n" ); document.write( "8hrs=8hrs \n" ); document.write( " \n" ); document.write( " |