document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=957373>Question 957373</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Kates age 5 years ago, when doubled, is equal to triple her age 10 years ago </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #585080 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=585080\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> K=Kate's age<BR>\n" );
document.write( "2(K-5yrs)=3(K-10yrs)<BR>\n" );
document.write( "2K-10yrs=3K-30yrs Add 30 yrs to each side.<BR>\n" );
document.write( "2K+20yrs=3K Subtract 2K from each side.<BR>\n" );
document.write( "20yrs=K ANSWER: Kate is 20 years old.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "2(K-5yrs)=3(K-10yrs)<BR>\n" );
document.write( "2(20yrs-5yrs)=3(20yrs-10yrs)<BR>\n" );
document.write( "2(15yrs)=3(10yrs)<BR>\n" );
document.write( "30yrs=30yrs </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );