document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=957441>Question 957441</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of each side of a square was increased by 3 inches, so the perimeter is now 40 inches.  What was the original length of each side of the square? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #585040 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=585040\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of each side of a square was increased by 3 inches, so the perimeter is now 40 inches. What was the original length of each side of the square?<BR>\n" );
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document.write( "Let original side length be \"s\" inches<BR>\n" );
document.write( "Then original perimeter = 4s inches<BR>\n" );
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document.write( "New permeter = 4(s+3) = 4s + 12<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "4s + 12 = 40<BR>\n" );
document.write( "4s = 28<BR>\n" );
document.write( "s = 7 inches<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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