document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=957403>Question 957403</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 5 inches more than 3 times the width. If the perimeter is 26, find the length and width. Could you send the solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #585027 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=585027\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=perimeter=26; W=width; L=length=3W+5in<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "26=2(L+W) Substitute for L<BR>\n" );
document.write( "26=2((3W+5in)+W)<BR>\n" );
document.write( "26=2(4W+5in) Divide each side by 2<BR>\n" );
document.write( "13=4W+5in Subtract 5in from each side<BR>\n" );
document.write( "8in=4W Divide each side by 4<BR>\n" );
document.write( "2in=W ANSWER 1: The width is 2 inches.<BR>\n" );
document.write( "L=3W+5=3(2in)+5in=11 in ANSWER 2: The length is 11 inches.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "26in=2(11in+2in)<BR>\n" );
document.write( "26in=2(13in)<BR>\n" );
document.write( "26in=26in </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );