document.write( "Question 957415: In triangle ABC, a = 4, b = 3, and cos C = -1/2. What is the length of c? \n" ); document.write( "
Algebra.Com's Answer #585024 by stanbon(75887)\"\" \"About 
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In triangle ABC, a = 4, b = 3, and cos C = -1/2. What is the length of c?
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\n" ); document.write( "c^2 = a^2+b^2-2ab*cos(C)
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\n" ); document.write( "c^2 = 16 + 9 - 2*4*3(-1/2)
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\n" ); document.write( "c^2 = 25-12
\n" ); document.write( "c = sqrt(13)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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