document.write( "Question 11227: what is the correct form of solving this problem:\r
\n" ); document.write( "\n" ); document.write( "132=n(n-1) \n" ); document.write( "

Algebra.Com's Answer #5850 by Earlsdon(6294) $\"\"$ $\"About$

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$\"132+=+n%28n-1%29\"$ Simplify.
\n" ); document.write( " $\"n%5E2+-+n+-+132+=+0\"$ Factor.
\n" ); document.write( " $\"%28n+-+12%29%28n+%2B+11%29+=+0\"$ Apply the zero product principle.
\n" ); document.write( " $\"n+-+12+=+0\"$ , $\"n+=+12\"$ or
\n" ); document.write( " $\"n+%2B+11+=+0\"$ , $\"n+=+-11\"$ \n" ); document.write( "

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