document.write( "Question 81550: Science and medicine. The equation h= -16t^2 + 112t gives the height of an
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document.write( "arrow, shot upward from the ground with an initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground. Find the time it takes for the arrow to reach a height of 180 ft. \n" );
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Algebra.Com's Answer #58478 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The equation h=-16t^2 + 112t gives the height of an arrow, shot upward from the ground with an initial velocity of 112 ft/s, where t is the time after the arrow leaves the ground. Find the time it takes for the arrow to reach a height of 180 ft. \n" ); document.write( ": \n" ); document.write( "Substitute 180 for h in the given equation: -16t^2 + 112t = h \n" ); document.write( ": \n" ); document.write( "-16t^2 + 112t = 180 \n" ); document.write( ": \n" ); document.write( "-16t^2 + 112t - 180 = 0; subtract 180 from both sides, gives us a quadratic eq: \n" ); document.write( ": \n" ); document.write( "Simplify divide equation by -4, that changes the signs and gives you: \n" ); document.write( "4t^2 - 28t + 45 = 0 \n" ); document.write( ": \n" ); document.write( "Factor this to: \n" ); document.write( "(2t - 5)(2t - 9) = 0 \n" ); document.write( ": \n" ); document.write( "2t = +5 \n" ); document.write( "t = 2.5 sec (on the way up) \n" ); document.write( "and \n" ); document.write( "2t = +9 \n" ); document.write( "t = 4.5 sec (on the way down) \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution using t = 2.5, in the original equation: \n" ); document.write( "-16(2.5^2) + 112(2.5) = \n" ); document.write( "-16(6.25) + 280 = \n" ); document.write( "-100 + 280 = 180 \n" ); document.write( ": \n" ); document.write( "You can check it using the t = 4.5 solution \n" ); document.write( " |