document.write( "Question 81460: How much must you deposit in an account that pays 6% annual interest compounded yearly to have a balance of $ 1000 after 10 years \n" ); document.write( "
Algebra.Com's Answer #58477 by bucky(2189)\"\" \"About 
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The equation that is used to solve this problem is:
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\n" ); document.write( "\"P+=+C%281+%2B+%28r%2Fn%29%29%5E%28n%2At%29\"
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\n" ); document.write( "in which the variables are:
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\n" ); document.write( "P is the future value of the invested money
\n" ); document.write( "C is the initial deposit
\n" ); document.write( "r is the interest rate expressed as a decimal
\n" ); document.write( "n is the number of times a year that the interest is compounded
\n" ); document.write( "t is the number of years of the investment
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\n" ); document.write( "For this problem the variables are given as follows:
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\n" ); document.write( "P is $1000
\n" ); document.write( "C is the amount of the initial deposit and you are to find C
\n" ); document.write( "r is 0.06 (the interest rate)
\n" ); document.write( "n is 1 compounding per year
\n" ); document.write( "t is 10 years
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\n" ); document.write( "Substituting these values into the equation results in:
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\n" ); document.write( "\"1000+=+C%281+%2B+%280.06%2F1%29%29%5E%281%2A10%29\"
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\n" ); document.write( "This simplifies to:
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\n" ); document.write( "\"1000+=+C%281+%2B+0.06%29%5E10\"
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\n" ); document.write( "and this further simplifies to:
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\n" ); document.write( "\"1000+=+C%281.06%29%5E10\"
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\n" ); document.write( "Calculator time. Use your calculator to raise 1.06 to the 10th power. Your calculator
\n" ); document.write( "may have a key for \"x%5Ey\". If it does, enter 1.06 then press the \"x%5Ey\" key, and
\n" ); document.write( "next enter 10 and then press the = key. You should get 1.790847697. You can also get
\n" ); document.write( "this by entering 1.06 on your calculator and then multiplying it 9 times by 1.06.
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\n" ); document.write( "Substitute 1.790847697 for \"%281.06%29%5E10\" and the equation becomes:
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\n" ); document.write( "\"1000+=+C%2A1.790847697\"
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\n" ); document.write( "Finally solve for C by dividing both sides by 1.790847697 to get:
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\n" ); document.write( "\"1000%2F1.790847697+=+C\"
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\n" ); document.write( "After doing the division on the left side the equation simplifies to:
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\n" ); document.write( "\"558.3947768+=+C\"
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\n" ); document.write( "Rounding this off to the next greatest cent tells you that to end up with at least $1000
\n" ); document.write( "you need to invest $558.40 at 6% interest compounded yearly for 10 years.
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\n" ); document.write( "(Note that if you invest $558.39 under the same circumstances you end up with $999.99 to the
\n" ); document.write( "nearest cent but by investing $558.40 you get $1000.01 to the nearest cent.)
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\n" ); document.write( "Hope this helps you to understand the problem a little better.
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