document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=956916>Question 956916</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a truck travels 20 mph faster than a train. in the same amount of time that the train travels 160 miles, the truck travels 240 mile. find the speed that each is traveling </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #584759 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=584759\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> r=rate of train<BR>\n" );
document.write( "160mi/r=240mi/(r+20mph) Cross multiply.<BR>\n" );
document.write( "160mi(r+20mph)=240r mi<BR>\n" );
document.write( "160r mi+3200mi^2/hr=240r mi Subtract 160r mi from each side.<BR>\n" );
document.write( "3200mi^2/hr=80r mi Divide each side by 80 mi<BR>\n" );
document.write( "40 mi/hr=r ANSWER 1: The train was traveling at 40 mi/hr.<BR>\n" );
document.write( "40 mi/hr+20 mi/hr=60 mi/hr ANSWER 2: The truck was traveling 60 mi/hr.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "160 mi/40 mph=240 mi/60mph<BR>\n" );
document.write( "4 hours=4 hours    </SPAN>\n" );
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