document.write( "Question 956947: A man is three times as old as his son. Ten years ago the sum of the square of their ages was 1250. find their ages
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Algebra.Com's Answer #584723 by macston(5194)\"\" \"About 
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M=man's age; S=son's age
\n" ); document.write( "M=3S
\n" ); document.write( "\"%28M-10%29%5E2%2B%28S-10%29%5E2=1250\" Substitute for M
\n" ); document.write( "\"%283S-10%29%5E2%2B%28S-10%29%5E2=1250\"
\n" ); document.write( "\"9S%5E2-60S%2B100%2BS%5E2-20S%2B100=1250\"
\n" ); document.write( "\"10S%5E2-80S%2B200=1250\" Subtract 1250 from each side.
\n" ); document.write( "\"10S%5E2-80S-1050=0\"\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"aS%5E2%2BbS%2Bc=0\" (in our case \"10S%5E2%2B-80S%2B-1050+=+0\") has the following solutons:
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\n" ); document.write( " \"S%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-80%29%5E2-4%2A10%2A-1050=48400\".
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\n" ); document.write( " Discriminant d=48400 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--80%2B-sqrt%28+48400+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"S%5B1%5D+=+%28-%28-80%29%2Bsqrt%28+48400+%29%29%2F2%5C10+=+15\"
\n" ); document.write( " \"S%5B2%5D+=+%28-%28-80%29-sqrt%28+48400+%29%29%2F2%5C10+=+-7\"
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\n" ); document.write( " Quadratic expression \"10S%5E2%2B-80S%2B-1050\" can be factored:
\n" ); document.write( " \"10S%5E2%2B-80S%2B-1050+=+10%28S-15%29%2A%28S--7%29\"
\n" ); document.write( " Again, the answer is: 15, -7.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+10%2Ax%5E2%2B-80%2Ax%2B-1050+%29\"

\n" ); document.write( "\n" ); document.write( "S=15 ANSWER The son is 15 years old.
\n" ); document.write( "M=3S=3(15yrs)=45yrs ANSWER 2: The man is 45 years old.
\n" ); document.write( "CHECK:
\n" ); document.write( "\"%28M-10%29%5E2%2B%28S-10%29%5E2=1250\"
\n" ); document.write( "\"%2845-10%29%5E2%2B%2815-10%29%5E2=1250\"
\n" ); document.write( "\"35%5E2%2B5%5E2=1250\"
\n" ); document.write( "\"1225%2B25=1250\"
\n" ); document.write( "\"1250=1250\"
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