document.write( "Question 956786: 2/r-5 + 3/2r+1 = 22/2r^2-9r-5 \n" ); document.write( "
Algebra.Com's Answer #584668 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"2%2F%28r-5%29+%2B+3%2F%282r%2B1%29+=+22%2F%28%282r%2B1%29%28r-5%29%29\"
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\n" ); document.write( "\"2%282r%2B1%29%2B3%28r-5%29=22\"
\n" ); document.write( "\"4r%2B2%2B3r-15=22\"
\n" ); document.write( "\"7r-13=22\"
\n" ); document.write( "\"7r=35\"
\n" ); document.write( "\"r=5\"
\n" ); document.write( "However, in eliminating the denominators we assumed that \"r-5%3C%3E0\" and \"2r%2B1%3C%3E0\" to avoid division by zero.
\n" ); document.write( "So \"r=5\" is not a possible solution.
\n" ); document.write( "No solution.
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