document.write( "Question 956905: The lengths of the right isosceles triangle are 8 cm, 11 cm, and 8 cm. Can you find the area of the triangle? If you can't explain why not. If you can, give the area and explain why you can. \n" ); document.write( "
Algebra.Com's Answer #584634 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
This is not a right isosceles triangle because it doesn't follow the Pythagorean theorem.
\n" ); document.write( "\"8%5E2%2B8%5E2%3C%3E11%5E2\"
\n" ); document.write( "However you can find the area.
\n" ); document.write( "Find the height of the triangle using 1/2 the base of 11 and the length 8 to form a right triangle.
\n" ); document.write( "\"H%5E2%2B%2811%2F2%29%5E2=8%5E2\"
\n" ); document.write( "\"H%5E2=8%5E2-%2811%2F2%29%5E2\"
\n" ); document.write( "\"H%5E2=64-121%2F4\"
\n" ); document.write( "\"H%5E2=256%2F4-121%2F4\"
\n" ); document.write( "\"H%5E2=135%2F4\"
\n" ); document.write( "\"H=sqrt%28135%29%2F2\"
\n" ); document.write( "\"H=%283%2F2%29sqrt%2815%29\"
\n" ); document.write( "So then the area is,
\n" ); document.write( "\"A=%281%2F2%29%2811%29%283%2F2%29sqrt%2815%29\"
\n" ); document.write( "\"A=%2833%2F4%29sqrt%2815%29\"\r
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