document.write( "Question 956881: Jen butler has been pricing speed pass train fares for a group trip to new York. three adults and four children must pay $121. two adults and three children must pay $86. find the price of the adults and the price of the child's ticket. \n" ); document.write( "
Algebra.Com's Answer #584603 by macston(5194)![]() ![]() You can put this solution on YOUR website! A=adult price; C=child price \n" ); document.write( "3A+4C=$121 Multiply equation by 2. \n" ); document.write( "6A+8C=$242 Subtract this below. \n" ); document.write( "2A+3C=$86 Multiply equation by 3. \n" ); document.write( "6A+9C=$258 Subtract equation from above. \n" ); document.write( "6A+8C=$242 \n" ); document.write( "C=$16 ANSWER 1: A child's ticket is $16. \n" ); document.write( "3A+4C=$121 \n" ); document.write( "3A=$121-4C \n" ); document.write( "3A=$121-$64 \n" ); document.write( "3A=$57n Divide each side by 3. \n" ); document.write( "A=$19 ANSWER 2: An adult ticket costs $19. \n" ); document.write( "CHECK: \n" ); document.write( "2A+3C=$86 \n" ); document.write( "2($19)+3($16)=$86 \n" ); document.write( "$38+$48=$86 \n" ); document.write( "$86=$86 \n" ); document.write( " \n" ); document.write( " |