document.write( "Question 956881: Jen butler has been pricing speed pass train fares for a group trip to new York. three adults and four children must pay $121. two adults and three children must pay $86. find the price of the adults and the price of the child's ticket. \n" ); document.write( "
Algebra.Com's Answer #584603 by macston(5194)\"\" \"About 
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A=adult price; C=child price
\n" ); document.write( "3A+4C=$121 Multiply equation by 2.
\n" ); document.write( "6A+8C=$242 Subtract this below.
\n" ); document.write( "2A+3C=$86 Multiply equation by 3.
\n" ); document.write( "6A+9C=$258 Subtract equation from above.
\n" ); document.write( "6A+8C=$242
\n" ); document.write( "C=$16 ANSWER 1: A child's ticket is $16.
\n" ); document.write( "3A+4C=$121
\n" ); document.write( "3A=$121-4C
\n" ); document.write( "3A=$121-$64
\n" ); document.write( "3A=$57n Divide each side by 3.
\n" ); document.write( "A=$19 ANSWER 2: An adult ticket costs $19.
\n" ); document.write( "CHECK:
\n" ); document.write( "2A+3C=$86
\n" ); document.write( "2($19)+3($16)=$86
\n" ); document.write( "$38+$48=$86
\n" ); document.write( "$86=$86
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