document.write( "Question 81622This question is from textbook Algebra 1
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document.write( ": How do you solve for x when it is in the denominator of a rational expression such as in the following:\r
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document.write( "1/8 - 3/5 = 1/x What are the restrictions? What is the solution? \n" );
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Algebra.Com's Answer #58460 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! THERE ARE NO RESTRICTIONS. \n" ); document.write( "FIRST YOU MUST COMBINE ALL THE FRACTIONS BY FINDING A COMMON DENOMINATOR LIKE 40. \n" ); document.write( "1/8=5*1/40=5/40 & -3/5=-3*8/40=-24/40 \n" ); document.write( "5/40-24/40=1/X \n" ); document.write( "(5-24)/40=1/X \n" ); document.write( "-19/40=1/X NOW CROSS MULTIPLY \n" ); document.write( "-19X=40 \n" ); document.write( "X=40/-19 \n" ); document.write( "X=-40/19 ANSWER. \n" ); document.write( "PROOF \n" ); document.write( "1/8-3/5=1/(-40/19) A FRACTION IN THE DENOMINATOR (-40/19) NEEDS TO BE INVERTED AND THEN MULTIPLIED BY THE NUMERATOR THUS: \n" ); document.write( "1/8-3/5=-19/40 \n" ); document.write( "5/40-24/40=-19/40 \n" ); document.write( "-19/40=-19/40 \n" ); document.write( " |