document.write( "Question 81622This question is from textbook Algebra 1
\n" ); document.write( ": How do you solve for x when it is in the denominator of a rational expression such as in the following:\r
\n" ); document.write( "\n" ); document.write( "1/8 - 3/5 = 1/x What are the restrictions? What is the solution?
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Algebra.Com's Answer #58460 by checkley75(3666)\"\" \"About 
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THERE ARE NO RESTRICTIONS.
\n" ); document.write( "FIRST YOU MUST COMBINE ALL THE FRACTIONS BY FINDING A COMMON DENOMINATOR LIKE 40.
\n" ); document.write( "1/8=5*1/40=5/40 & -3/5=-3*8/40=-24/40
\n" ); document.write( "5/40-24/40=1/X
\n" ); document.write( "(5-24)/40=1/X
\n" ); document.write( "-19/40=1/X NOW CROSS MULTIPLY
\n" ); document.write( "-19X=40
\n" ); document.write( "X=40/-19
\n" ); document.write( "X=-40/19 ANSWER.
\n" ); document.write( "PROOF
\n" ); document.write( "1/8-3/5=1/(-40/19) A FRACTION IN THE DENOMINATOR (-40/19) NEEDS TO BE INVERTED AND THEN MULTIPLIED BY THE NUMERATOR THUS:
\n" ); document.write( "1/8-3/5=-19/40
\n" ); document.write( "5/40-24/40=-19/40
\n" ); document.write( "-19/40=-19/40
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