document.write( "Question 956835: The perimeter of a rectangle is 36 yards and the length is 15 yards. What is the rectangles width?
\n" ); document.write( "a) 21 yd
\n" ); document.write( "b) 6 yd
\n" ); document.write( "c) 3 yd
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Algebra.Com's Answer #584571 by macston(5194)\"\" \"About 
You can put this solution on YOUR website!
P=perimeter; L=length; W=width
\n" ); document.write( "\"P=2%28L%2BW%29\" Divide each side by 2.
\n" ); document.write( "\"P%2F2=L%2BW\" Subtract L from each side.
\n" ); document.write( "\"P%2F2-L=W\" Plug in numbers.
\n" ); document.write( "\"36yd%2F2-15yd=3yds\" ANSWER: The width is 3 yards.
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