document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=81539>Question 81539</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the slope of any line perpendicular to the line through points (3, 12) and (5, 4). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #58457 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=58457\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE SLOPE OF A LINE THROUGH THESE 2 POINTS IS<BR>\n" );
document.write( "(Y2-Y1)/(X2-X1)<BR>\n" );
document.write( "(4-12)/(5-3)<BR>\n" );
document.write( "-8/2<BR>\n" );
document.write( "-4 IS THE SLOPE. <BR>\n" );
document.write( "THUS FOR ANY LINE TO BE PERPENDICULAR TO THIS LINE IT MUST HAVE A SLOPE OF 1/4 (THE NEGATIVE RECIPRICAL OF 4).  <BR>\n" );
document.write( " </SPAN>\n" );
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