document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=956793>Question 956793</A>: <I><SPAN STYLE=\"word-break: break-all;\"> alice is counting a cash register at the end of the night. he has $1015 in $5 bills and $10 bills. if she has 138 bills all together, how many of each type does she have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #584546 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=584546\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's call the $5 a and the tens b<BR>\n" );
document.write( "a+b= 138 (equation 1), and therefore a= 138-b<BR>\n" );
document.write( "5a+10b= 1015 (equation 2) Now, in this equation we substitute the value of a, since we just said that a= 138-b:<BR>\n" );
document.write( "5(138-b)+10b= 1015<BR>\n" );
document.write( "690-5b+10b= 1015<BR>\n" );
document.write( "690+5b= 1015<BR>\n" );
document.write( "5b= 325<BR>\n" );
document.write( "b= 325/5<BR>\n" );
document.write( "b= 65, and since we said that a= 138-b:<BR>\n" );
document.write( "a= 138-65 = 73<BR>\n" );
document.write( "Check: (65 x 10) + (73 x 5)= 650 + 365= 1015 Correct.\r<BR>\n" );
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