document.write( "Question 956774: The sum of five times a number and twice a second number is 18, but the difference of three times the first number and seven times the second number is -22. Find the two numbers using the elimination method.
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Algebra.Com's Answer #584539 by stanbon(75887)\"\" \"About 
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The sum of five times a number and twice a second number is 18, but the difference of three times the first number and seven times the second number is -22. Find the two numbers using the elimination method.
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\n" ); document.write( "Equations:
\n" ); document.write( "5x + 2y = 18
\n" ); document.write( "3x - 7y = -22
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\n" ); document.write( "Modify for elimination::
\n" ); document.write( "15x + 6y = 3*18
\n" ); document.write( "15x - 35y= 5*-22
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\n" ); document.write( "Subtract and solve for \"y\"::
\n" ); document.write( "41y = 164
\n" ); document.write( "y = 4
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\n" ); document.write( "Solve for \"x\"::
\n" ); document.write( "3x - 7y = -22
\n" ); document.write( "3x - 28 = -22
\n" ); document.write( "3x = 6
\n" ); document.write( "x = 2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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