document.write( "Question 956739: A merchant sells one type of tea for $5.50 per pound and a second type for $4.25 per pound. She wishes to mix the tea to form a 60 lb mixture that will sell for $4.55 per pound. How many pounds of each type of tea should be used in the mixture? \n" ); document.write( "
Algebra.Com's Answer #584530 by stanbon(75887)\"\" \"About 
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A merchant sells one type of tea for $5.50 per pound and a second type for $4.25 per pound. She wishes to mix the tea to form a 60 lb mixture that will sell for $4.55 per pound. How many pounds of each type of tea should be used in the mixture?
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\n" ); document.write( "Quantity:: a + b = 60 lbs
\n" ); document.write( "Value::: 550a+425b = 455*60
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\n" ); document.write( "Modify for elimination:
\n" ); document.write( "550a + 550b = 550*60
\n" ); document.write( "550a + 425b = 455*60
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\n" ); document.write( "Subtract and solve for \"b\":
\n" ); document.write( "125b = 95*60
\n" ); document.write( "b = (19/25)60
\n" ); document.write( "b = 45.6 lbs (amt. of $4.25 tea needed)
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\n" ); document.write( "a = 60-45.6 = 14.4 lbs (amt of $5.50 tea needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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