document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=81580>Question 81580</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a car traveled at an average rate of 40 mph and then reduced its average rate to 30mph for the rest of the trip. if the 180 mile trip took five hour, determine how long the car traveled at each rate.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #58453 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=58453\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 40X+30(5-X)=180<BR>\n" );
document.write( "40X+150-30X=180<BR>\n" );
document.write( "10X=180-150<BR>\n" );
document.write( "10X=30<BR>\n" );
document.write( "X=3 HOURS @ THE 40 MPH RATE &<BR>\n" );
document.write( "5-3=2 HOURS @ THE 30 MPH RATE.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "40*3+30*2=180<BR>\n" );
document.write( "120+60=180<BR>\n" );
document.write( "180=180 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );