document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=956656>Question 956656</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of three numbers is 39. the sum of the first and second is twice the third. the sum of the second and the third is 3 more than twice the first. find the third number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #584479 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=584479\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+Y+Z=39<BR>\n" );
document.write( "X+Y=2Z <BR>\n" );
document.write( "Y+Z=2X+3<BR>\n" );
document.write( "REPLACE (X+Y) WITH 2Z IN THE FIRST EQUATION<BR>\n" );
document.write( "2Z+Z=39<BR>\n" );
document.write( "3Z=39<BR>\n" );
document.write( "Z=39/3<BR>\n" );
document.write( "Z=13 ANS.<BR>\n" );
document.write( "X+Y+13=39<BR>\n" );
document.write( "X+Y=39-13<BR>\n" );
document.write( "X+Y=26<BR>\n" );
document.write( "Y+13=2X+3<BR>\n" );
document.write( "Y-2X=3-13<BR>\n" );
document.write( "Y-2X=-10<BR>\n" );
document.write( "Y=2X-10 <BR>\n" );
document.write( "REPLACE Y WITH 2X-10 & SOLVE FOR X<BR>\n" );
document.write( "X+(2X-10)=26<BR>\n" );
document.write( "3X=26+10<BR>\n" );
document.write( "3X=36<BR>\n" );
document.write( "X=36/3<BR>\n" );
document.write( "X=12 ANS.<BR>\n" );
document.write( "Y=2*12-10=24-10=14 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "12+14+13=39\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );