document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=81597>Question 81597</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do u solve the following equation?  3n=-2-4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #58446 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=58446\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve:<BR>\n" );
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document.write( "3n = -2 - 4<BR>\n" );
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document.write( "combine the two numbers on the right side by addition of negative numbers to get:<BR>\n" );
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document.write( "3n = -6<BR>\n" );
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document.write( "Solve for n by dividing both sides by 3.  This division makes the equation become:<BR>\n" );
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document.write( "(3/3)*n = (-6/3)<BR>\n" );
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document.write( "which simplifies to:<BR>\n" );
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document.write( "1*n = -2<BR>\n" );
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document.write( "or simply:<BR>\n" );
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document.write( "n = -2<BR>\n" );
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document.write( "Check by substituting this value for n in the original equation that you were given.<BR>\n" );
document.write( "This substitution results in:<BR>\n" );
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document.write( "3n = -2 - 4<BR>\n" );
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document.write( "becoming:<BR>\n" );
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document.write( "3*(-2) = -2 - 4<BR>\n" );
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document.write( "the left side multiplies out to:<BR>\n" );
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document.write( "-6 = -2 - 4<BR>\n" );
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document.write( "and the right side adds to -6.  So the equation works because it results in:<BR>\n" );
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document.write( "-6 = -6<BR>\n" );
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document.write( "Hope this helps you to understand some of the basic methods of solving linear equations.<BR>\n" );
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