document.write( "Question 956620: The sum of the ages of a boy and his mother is 48. If the mother is three more than twice the
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document.write( "boy’s age, find the difference in the ages of the boy and his mother.
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Algebra.Com's Answer #584441 by aliokur(1)![]() ![]() ![]() You can put this solution on YOUR website! B=Ages of boy \n" ); document.write( "M=Ages of mother\r \n" ); document.write( "\n" ); document.write( "B+M=48 => M=48-B and B=48-M \n" ); document.write( "2B+3=M\r \n" ); document.write( "\n" ); document.write( "2B+3=M => 2B+3=48-B => 3B=51 => B=17\r \n" ); document.write( "\n" ); document.write( "M=48-B=48-17=31\r \n" ); document.write( "\n" ); document.write( "M-B=31-17=14 \n" ); document.write( " |