document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=956493>Question 956493</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ax </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #584347 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=584347\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this question.\r<BR>\n" );
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document.write( "One canned juice drink is 25% orange juice; another is 5% orange juice. How many liters of each should be mixed together in order to get 20L that is 8% orange juice?<BR>\n" );
document.write( "Let x=liters of 25% solution needed<BR>\n" );
document.write( "Then 20-x=liters of 5% solution needed<BR>\n" );
document.write( "Now we know that the pure orange juice that exists before the mixture takes place (0.25x+0.05(20-x)) has to equal the pure orange juice that exists after the mixture takes place (0.08*20).<BR>\n" );
document.write( "Sooooo<BR>\n" );
document.write( "0.25x+0.05(20-x)=0.08*20<BR>\n" );
document.write( "0.25x+1-0.05x=1.6<BR>\n" );
document.write( "0.20x=0.6<BR>\n" );
document.write( "x=3 liters -----amount of 25% solution needed<BR>\n" );
document.write( "20-x=20-3=17 liters amount of 5% solution needed<BR>\n" );
document.write( "Hope this helps----ptaylor </SPAN>\n" );
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