document.write( "Question 956490: Brianna invests $2400 in one account and $1900 in an account paying 2 % higher interest. At the end of one year she had earned $382 in interest. At what rates did she invest? \n" ); document.write( "
Algebra.Com's Answer #584344 by macston(5194)![]() ![]() You can put this solution on YOUR website! I=lower interest rate (decimal) \n" ); document.write( "$2400I+$1900(I+.02)=$382 \n" ); document.write( "$2400I+$1900I+$38=$382 Subtract $38 from each side \n" ); document.write( "$4300I=$344 Divide each side by $4300 \n" ); document.write( "I=0.08 ANSWER 1: The lower rate was 8%. \n" ); document.write( "I+2%=8%+2%=10% ANSWER 2: The higher rate was 10%. \n" ); document.write( "CHECK: \n" ); document.write( "$2400(0.08)+$1900(0.10)=$382 \n" ); document.write( "$192+$190=$382 \n" ); document.write( "$382=$382 \n" ); document.write( " |