document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=956419>Question 956419</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 126 m. The length is 3 m more than twice the width. Find the dimensions. I struggled with trying to figure this question out. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #584341 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=584341\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=width: L=length=2W+3m; P=perimeter<BR>\n" );
document.write( "P=2(L+W) Substitute for L.<BR>\n" );
document.write( "126m=2((2W+3m)+W) Divide each side by 2.<BR>\n" );
document.write( "63m=3W+3m Subtract 3m from each side.<BR>\n" );
document.write( "60m=3W Divide each side by 3.<BR>\n" );
document.write( "20m=W ANSWER 1: The width is 20 meters.<BR>\n" );
document.write( "L=2W+3m=2(20m)+3m=43m ANSWER 2: The length is 43 meters.<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "126m=2(43m+20m)<BR>\n" );
document.write( "126m=2(63m)<BR>\n" );
document.write( "126m=126m  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );