document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=956436>Question 956436</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a number is double and then increased by 9. the result is 57. find the original number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #584333 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=584333\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2X+9=57<BR>\n" );
document.write( "2X=57-9<BR>\n" );
document.write( "2X=48<BR>\n" );
document.write( "X=48/2<BR>\n" );
document.write( "X=24 ANS.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "2*24+9=57<BR>\n" );
document.write( "48+9=57<BR>\n" );
document.write( "57=57 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );