document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=956212>Question 956212</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 12. On the first part of a road trip to Batangas travelling on the highway, Kelly averages 60 kph. On the rest of the roadtrip, which was 10 kilometers longer than the first part, she averaged 50 kph. Find the total distance to Batangas if the second part of the trip took 30 minutes more than the first.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #584329 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=584329\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  On the first part of a road trip to Batangas travelling on the highway, Kelly averages 60 kph.<BR>\n" );
document.write( " On the rest of the roadtrip, which was 10 kilometers longer than the first part, she averaged 50 kph.<BR>\n" );
document.write( " Find the total distance to Batangas if the second part of the trip took 30 minutes more than the first.<BR>\n" );
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document.write( "let d = distanced traveled the first part of the trip at 60 kph<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(d+10) = distance traveled the second part at 50 kph, (10 km longer)<BR>\n" );
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document.write( "Change 30 min to 1/2 hr<BR>\n" );
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document.write( "Write a time equation; time = dist/speed<BR>\n" );
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document.write( "50kph time - 60kph time = 1/2 hr<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28%28d%2B10%29%29%2F50 ALIGN=MIDDLE  ALT=\"%28%28d%2B10%29%29%2F50\"   DISABLED_style= \"max-width:90%; height:auto;\" > - <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d%2F60 ALIGN=MIDDLE  ALT=\"d%2F60\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F2 ALIGN=MIDDLE  ALT=\"1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "multiply by 300 to cancel the denominators, then you have:<BR>\n" );
document.write( "6(d+10) - 5d = 150<BR>\n" );
document.write( "6d + 60 - 5d = 150<BR>\n" );
document.write( "6d - 5d = 150 - 60<BR>\n" );
document.write( "d = 90 km is the 1st part of the trip<BR>\n" );
document.write( "then<BR>\n" );
document.write( "90 + 10 = 100 km is the 2nd part<BR>\n" );
document.write( "and<BR>\n" );
document.write( "90 + 100 = 190 km is the total distance to Batangas. Philippines?<BR>\n" );
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document.write( "Confirm this, find the actual time of each part of the trip<BR>\n" );
document.write( "100/50 = 2 hrs<BR>\n" );
document.write( "90/60 = 1.5 hrs<BR>\n" );
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document.write( "time dif: .5 hrs </SPAN>\n" );
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