document.write( "Question 956406: 1. Determine the domain and range for f(x)=3+√(x-5).
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Algebra.Com's Answer #584289 by Edwin McCravy(20055) $\"\"$ $\"About$

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document.write( "f(x) and y are the same thing. So write it as:\r\n" );
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document.write( "What's under the square root, x-5, cannot be negative so it must be\r\n" );
document.write( "greater than or equal to 0, so we have:\r\n" );
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document.write( "So the domain is the set of all x-values greater than or equal to 5.\r\n" );
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document.write( "{x | x ≥ 5} or in interval notation: [5,)\r\n" );
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document.write( "Since the square root  is never negative we can write\r\n" );
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document.write( "We can add 3 to both sides to make the right side of f(x) above:\r\n" );
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document.write( "And since  \r\n" );
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document.write( "So the range is the set of all y-values greater than or equal to 3.\r\n" );
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document.write( "{y | y ≥ 3} or in interval notation: [3,).  \r\n" );
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document.write( "f∘g(x) = , so we substitute the right side of\r\n" );
document.write( "g(x) for x in the right side of f(x).\r\n" );
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document.write( "f∘g(x).\r\n" );
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document.write( "Edwin

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