document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=956409>Question 956409</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is six times its width. <BR>\n" );
document.write( "If the perimeter of the rectangle is <BR>\n" );
document.write( "84 yd, find its area. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #584280 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=584280\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=width; L=length=6W; P=perimeter=84yds; A=area<BR>\n" );
document.write( "P=2(L+W) Substitute for L.<BR>\n" );
document.write( "84yds=2(6W+W) <BR>\n" );
document.write( "84yd=12W+2W<BR>\n" );
document.write( "84yd=14W Divide each side by 14.<BR>\n" );
document.write( "6yd=W  The width of the rectangle is 6 yards.<BR>\n" );
document.write( "L=6W=6(6yd)=36 yards The length is 36 yards.<BR>\n" );
document.write( "A=L*W<BR>\n" );
document.write( "A=36yd*6yd=216 sq yd ANSWER: The area is 216 square yards. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );